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Begin privacyenhanced message proctype 01,micclear originatorname webmaster@wwwsecgov originatorkeyasymmetric. Who or what should she believe?. Has a fixed point at p precisely when f(p) = 0, where f(x) = x42x2−x−3 Solution (a)x = g1(x) ⇒x = (3x−2x2)1/4 ⇒x4 = 3x−2x2 ⇒x42x2−x−3 = 0 ⇒ f(x) = 0 (b) x = g2(x) ⇒ x = x3−x4 2 1/2 ⇒ x2 = x3− 4 2 ⇒ 2x2 = x 3− x4 ⇒ x4 2x2 −x −3 = 0 ⇒ f(x) = 0 1 (c) x = g3(x) ⇒ x = x3 x22 1/2 ⇒ x2 = x3 x22 ⇒ x 4 2x2 = x 3 ⇒ x4 2x2 −x −3 = 0.

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