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= ( 1 / ln b) e (ln b) x C 2 = ( 1 / ln b) ( e (ln b)) x C 2 = ( 1 / ln b) b x C 2 = b x / ln b C 2 QED See also the proof of e u du = e u PROOF 2 You need not memorize this theorem Derive it each time you use it Consider this example if you have the integral 2 x dx There is no need to memorize the formula We will get this. Z u C f B O N u ł́A { l C X g N ^ ɂ n ̌ i S Ҋ } j A { C M X ̃ C Z X 擾 ܂ŗl X ȃR X ŊF l ҂ Ă ܂ B. B where a is the beginning of the interval and b is the end of the interval The Uniform Distribution derives ’naturally’ from Poisson Processes and how it does will be covered in the Poisson Process Notes.
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} R e B O t B { H z C C G A ̎ t V g y A ͗A ԁi O ԁj X f ^ ܂ / l/ s } J r e B @ f ^ _ ސ쌧 l s s } F @TEL. ɂ ӂ ̃C j V ō I W i E G f B O S } N ̃f U C ̓X L b v f U C s N ` Y ŁI. In probability theory and statistics, the cumulative distribution function (CDF) of a realvalued random variable, or just distribution function of , evaluated at , is the probability that will take a value less than or equal to Every probability distribution supported on the real numbers, discrete or mixed as well as continuous, is uniquely identified by an upwards continuous monotonic.
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