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The Lambert W function has many different branches, which is something sort of akin to the fact that when you take a square root you can choose either the positive or negative square root This means that there isn't a unique solution to your equation. X x 6 xÞs ã. Compute answers using Wolfram's breakthrough technology &.

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Feb 22, 15There's always the taxicab identity $$ 12^31^3 = 10^39^3 $$ It is not known whether examples exist for all exponents For fourth powers there is $$ 133^4 134^4 = 158^4 59^4 $$ but even for fifth powers no example is known (nor a proof that there are no examples). Simple and best practice solution for xy=w equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand,. Zs 6 t ³.

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N s X x ZÞ. It looks as if you may have reached the right integral, which is ∫ 0 1 2 π x e − x 2 d x You can quickly integrate by making the substitution u = x 2 How to compute \int_0^1 {e^{x^2}} dx. Zs _ x ` X N w á.

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X X 6 5s . In elementary algebra, the binomial theorem (or binomial expansion) describes the algebraic expansion of powers of a binomialAccording to the theorem, it is possible to expand the polynomial (x y) n into a sum involving terms of the form ax b y c, where the exponents b and c are nonnegative integers with b c = n, and the coefficient a of each term is a specific positive. X X Xs ã.

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Jul 29, 14The information in this report is being furnished, not filed, pursuant to Regulation FD Accordingly, the information in Items 701 and 901 of this report will not be incorporated by reference into any registration statement filed by the Company under the Securities Act of 1933, as amended, unless specifically identified therein as being incorporated therein by reference. S üÞs Xs ü. Knowledgebase, relied on by millions of students &.

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But then E(XjY =y)=åx xfXjY(xjy)=åx xfX(x)=E(X) 2 2 EE(g(X)jY)=E(g(X)) Proof Set Z = g(X) Statement (i) of Theorem 1 applies to any two rv’s Hence, applying it to Z and Y we obtain EE(ZjY)= E(Z) which is the same as EE(g(X)jY)= E(g(X)) 2 This property may seem to be more general statement than (i) in Theorem 1 The proof above. Ns ` x . üs sO xE ÞO (.

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6 t E ãÞ. üs_ O x X ã. (1 point) If the series y() CIxn s a solution of the differential equation ly' 5y ly 0, then cut n2 n0 cn, n 0, 1, 2 A general solution of the same equation can be written as y(x coy1(x) c1y2Ca), where 2n an x n0 2n1 bnx Calculate a2 a3.

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`s s X E 6s ü. May 31, 19Let X and Y be two independent \\mathcal{N}(0,1) random variables and Z=1XXY^2 W=1X I want to find Cov(Z,W) Solution Cov(Z,W)=Cov(1XXY^2,1X) Cov(Z,W)=Cov(XXY^2,X) Cov(Z,W)=Cov(X,X)Cov(XY^2,X) Cov(Z,W)=Var(X)E(X^2Y^2)E(XY^2)E(X) Cov(Z,W)=1E(X^2)E(Y^2)E(X)^2E(Y^2). X E O _s O x N .

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Jun 17, 16eliminate the arbitrary constant y=c 1 e x c 2 xe x y'=c 1 e x c 2 (xe x e x) y''=c 1 e x c 2 (xe x 2e x) by comparing eq1 and eq,2 = eq,4 by comparing eq2 and eq3 = eq5 by comparing eq4 and eq5 = y'' 2y 3y'. X s Xs .