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ò tdt=8e12 C When t=0,v=0 0=8CÞC=8 v=8e12t8 The distance moved in the interval 0 2 t is given by s= vdt 0 ò2 = 8e12t8 0 ò2 dt =é16e12t8t ë ù û0 2 =(16e116)16 =16e32 =115 (3 sf) The distance moved is 115 m (3 sf) 5 a Let the acceleration of P at time t be a m s–2 v=4cos 3t So a= dv dt =12sin3t When t= p 12 a=12sin p 4. ñ í î ì ì ô í õ ð ì í î ì ï î ò t o o o ( } } µ u v À ( } v d,/^ /^ t/d, Z & Z E dK KhZ s Zd/^D Ed s/ EK /K > lD. Title Microsoft Word Tn of Pawlet v Banyai No Vtec (Merits Decision) () Author dchamber Created Date 3/5/21 PM.
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Standard ACE DB µn b` ÂUé©gr@?œ~Ÿ ÿš1Åyºí0¼ßÌ cÙäßFûŠ¼NWSì7Œìœú ö(æ Š` SobOYbU kdoiMQk ž € ‚ !. Title Microsoft PowerPoint Microaggressions_Peds Faculty Development August 19 Author ploofdl Created Date 1/30/ PM. ò T 5 5T 5 6 T 6 5 6 7 V 5 7 V 6 6 D xi represents the elementwise adversarial loss function D y represents the adversarial loss function for the label CE represents the crossentropy loss Data are missing at random (MAR) In this case, the pattern.
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