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Set u = sec x tan x then we find du = (sec x tan x sec 2 x) dx substitute du = (sec x tan x sec 2 x) dx, u = sec x tan x.

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U = x 2 2x3 Then the derivative of u is Now "pretend" that the differentiation notation is an arithmetic fraction, and multiply both sides of the previous equation by dx getting or du = (2x2) dx Make substitutions into the original problem, removing all forms of x, resulting in = e u C = e x. Â Ê < 2 § ó ¼ æ Ã ¡ c Ý å Ù ´ ) ¦ Æ ¸ ¡ ¦ Ý ² ç Ù ¶ î ² ¦ ² ¸ î Å Æ v Ê $ r Ù ^ É ø ¦ ä ® É ö í ì Ö ¦ Ô Ù ´ > > J $ r Ù ^ ø r Æ r × ã å J > * Æ Ê ² Á ï Æ Ê Å ä Å ¦ ¾ º Ã ì ¾ Á. U P V W X O P Y L Z N P M N W H P Z N \ \ O Q H L W K N X W M R ^ O L M H N P _ ` S a L M H N P L W S ^ ^ N L Q J , C ?.

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Suites Et Series De Fonctions

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