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Feb 06, 18 · f^(n)(x) = 3n e^x 3xe^x, where n is an integer We can immediately see that f'(x) = 3e^x 3xe^x f''(x) = 3e^x 3e^x 3xe^x = 6e^x 3xe^x f'''(x) = 6e^x 3e^x 3xe^x = 9e^x 3xe^x So the pattern is f^(n)(x) = 3n e^x 3xe^x, where n is an integer Hopefully this helps!. 0Ì 7b e L@ !. 4s 4y 4î 4_ 4F 4!, 4¥ 4 4 4ƒ 4‹ 4& 4r 4 4K& 4 $ 4A% 4‚ 4' 4H> 4;.
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